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instance_path for namespace packages uses path closest to submodule

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Evgeny Prigorodov 2022-05-26 21:12:36 +02:00 • committed by David Lord
parent fb89745408
commit 88bcf78439
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3 changed files with 48 additions and 12 deletions
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19
tests/test_instance_config.py
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@ -59,6 +59,25 @@ def test_uninstalled_package_paths(modules_tmpdir, purge_module):
assert app.instance_path == str(modules_tmpdir.join("instance"))
def test_uninstalled_namespace_paths(tmpdir, monkeypatch, purge_module):
def create_namespace(package):
project = tmpdir.join(f"project-{package}")
monkeypatch.syspath_prepend(str(project))
project.join("namespace").join(package).join("__init__.py").write(
"import flask\napp = flask.Flask(__name__)\n", ensure=True
)
return project
_ = create_namespace("package1")
project2 = create_namespace("package2")
purge_module("namespace.package2")
purge_module("namespace")
from namespace.package2 import app
assert app.instance_path == str(project2.join("instance"))
def test_installed_module_paths(
modules_tmpdir, modules_tmpdir_prefix, purge_module, site_packages, limit_loader
):